Voltage drop at ballast resistor

No sorry, I don't. Plus there are many ways of implementing this. So called "Bosch" relays have a fairly standard wiring scheme.

mini-automotive-relay-wiring-840x.jpg

30 is for main power to feed the load coming TO the relay. So for example, run a say, 20A automotive breaker from the big stud on the starter relay to no30

87A is not used in this situation. This is "normally closed" meaning when the relay is NOT powered that 87A and 30 make connection

87 is what you want to feed your load. When I say "cut" I mean functionally, electrically. How you PHYSICALLY do so is up to you. "Cut" the dark blue "ignition run" wire just as it comes out of the bulkhead and BEFORE it gets to the resistor. Connect the end which goes to the resistor here to 87

85 is the magnetic coil terminal GROUND this

86 is the other coil terminal, you feed power TO this to activate the relay. So now take the cut end of the dark blue that comes out of the bulkhead and connect to this terminal.

A little voltage drop in the harness now won't matter, all it has to do is to activate the relay. Now the ignition and VR will be fed from the starter relay "big stud" through the breaker through the relay and to the VR and ignition system.

Make sure you keep the breaker and relay away from engine heat and water leakage. You normally should mount these relays with terminals pointing down to further shed water