I appreciate the help, but that is still not what I wanted to know ;) I don't know how else to say it - how far does the clutch rod have to move the fork?
However, I got the answer a long time ago by asking Centerforce directly. Their reply:
The disc will be released with an 0.030” air gap. Linear travel at the bearing is 3/8” to release. Bearing load is 500 lbs.
Then I contacted Brewer's to ask what the ratio of the fork is:
Center of pivot point to center of clutch bearing 3.25"
Center of pivot point to center of clutch linkage eyelet 6.5"
That would be a 2:1 ratio.
So - with the free play taken up. 3/8" * 2 =
3/4" movement at the original fork actuating rod hole.
I haven't been underneath in a while, but I found that a little more movement was better for full disengagement.
:thumbsup: