If the diameter of the roller is 1/2 inch, its circumference is 1.5708 inches. 2 x pi x radius. So if it “rolls” 5/16 of an inch, it “rolls” less than 1/6 of its circumference, or .3125/1.5708=.1989. Now 5% scrub would be .95 x .1989.=.18899. So every 7 or so times the valve actuates, the roller would spin totally around. This would promote even roller wear and reduce friction and in turn heat.