I'm might not be thinking correctly but here is how I see it.
For this example there is no reversion. Air (oxygen) and fuel are drawn into the cylinder as a rich mixture. Enough to cause a misfire. During this cycle what would be left over is unburned fuel and oxygen. Of the two the o2 sensor only detects oxygen. Oxygen in a higher proportion than if normal combustion had occurred. I think the o2 sensor will read that as lean.
In order for reversion to cause the o2 sensor to read this as a rich mixture it would have to selectively reverse only the unburned fuel past the o2 sensor and none of the unburned oxygen. Diluting the left over oxygen to the point of reading rich.
Again I'm not saying this is right.