Here you go, Piston area and force.
Now you are mixing entities. I am not disputing more [ or less ] tq from the engine families you just listed. There is more than just piston size & stroke that determine the actual TQ/HP an engine produces.
No ****, but bore and stroke is what were talking about and isolate as best as can be.
Efficiency of the ports, induction & exh systems, friction etc will all affect the tq produced.
I am disputing something far more simple: just raw high school physics. I have already given YOU this example, but it seems the message did not get through.....
Two engines, different bore & stroke, but same cubic inches & same compression ratio. One engine has a 4" piston, other engine 4.25" piston. Both engines produce 1000lbs of force in the chamber at the completion of the mixture burn. 1000 lbs to push on the piston. Your argument is that because the 4.25" piston has more area, it will have more force applied to it than the 4" piston. Nope. Started with 1000 lbs, so it cannot be greater than that. What it means is this: the 4" piston has 80 llbs/ sq in of pressure on it & the larger 4.25" piston has 70 lbs/ sq in [ numbers rounded off ]. That is what this link explains....
Combustion is in psi, you keep saying in lbs, yes if both engines combustion was a 1000 lbs of force then your right but were talking psi, there is no reason that both of these engines wouldn't have similar psi, also it's not just a singular amount of psi it's the average psi of the complete power stroke.
Like I've said and everyone else has said from the beginning if the psi is the same the force of the piston will be more for the larger piston, I imagine you agree with that statement, now if you don't think the same psi is possible please explain why, saying both engines have a 1000 lbs of force isn't an explanation.
Again this ain't a formula for power, it's away to rank an engines power, like hp per cid, hp per L, hp per piston surface area. Really has no bearing on the discussion.
Unless you can show a valid reason why a larger piston, shorter stroke would have less average psi than a smaller piston, longer stroke engine of same displacement on average for similar level of efficiency.
Then there's really nothing more to discuss.
*Edit, And this (below) explains that so unless you can prove below has no bearing on what were discussing think were done.
Ideal gas law is P = nRT / V
The Main ones that concern this discussion are Pressure = Temperature / Volume