Here you go, Piston area and force.

Now you are mixing entities. I am not disputing more [ or less ] tq from the engine families you just listed. There is more than just piston size & stroke that determine the actual TQ/HP an engine produces. Efficiency of the ports, induction & exh systems, friction etc will all affect the tq produced.

I am disputing something far more simple: just raw high school physics. I have already given YOU this example, but it seems the message did not get through.....

Two engines, different bore & stroke, but same cubic inches & same compression ratio. One engine has a 4" piston, other engine 4.25" piston. Both engines produce 1000lbs of force in the chamber at the completion of the mixture burn. 1000 lbs to push on the piston. Your argument is that because the 4.25" piston has more area, it will have more force applied to it than the 4" piston. Nope. Started with 1000 lbs, so it cannot be greater than that. What it means is this: the 4" piston has 80 llbs/ sq in of pressure on it & the larger 4.25" piston has 70 lbs/ sq in [ numbers rounded off ]. That is what this link explains....

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When you state 1000# force in the cylinder, I assume you mean PSI. That PSI spread over a larger piston area creates more force in pounds pushing the piston and thus the con rod down.
More force on a shorter stroke will probably equalize the maximum torque developed, but at higher RPM. This boils down to more HP at higher RPM. The shorter stroke will give lower piston speed at any given RPM, so there is less loss to friction.