Here you go, Piston area and force.
Dale
You are 100% wrong in post #125, with 'PSI spread over a larger area creates more force'.
It's literally in it's name PSI, Pounds Per Square Inches, Force = Pounds Per Square Inches x Amount of Square Inches, Eg.. 1 psi x 100 square inches of surface area = 100 lbs of force.
Look at post #130. Pressure = force divided by area.
Were not looking for pressure, were looking for what the pressure does to the piston, were looking for the force the piston is passing on to the crank which is Force = pressure x area.
The force or pressure [ or whatever you want to call it ]
It matters a lot what it's called.
is created by the expanding gas. I used an example of 1000 what-u-ma-call-its. Call it what you like & whatever quantity.
Again psi, basically pressure = temperature / volume, P = nRT / V
The point is that the loading per sq in is less on the bigger piston even though both small & large pistons had the same initial force/pressure applied.
Again they both have the same psi, again pressure = nR Temperature / Volume of combustion chamber opening into total volume of the cylinder. Area doesn't have anything to do with the psi created by the combustion process. I know that don't jive with your coin and playdough or water hose and dog **** analogies, but maybe you should use science that's related to the topic.
That is what the picture in post #130 shows: the flat coin did not sink into the plasticine as it did on it's end because the loading per area was less even though the same initial force was used.
This is your issue, your basing your whole argument on this, maybe should be on how combustion actually creates pressure, psi. Do some research on the combustion process.
I have already given this example, but maybe you missed it. The piston transmits it's load
Force
to the crank via the pin & conrod. If I make the rod eye wider, according to your theory, because I have increased the area, the rod now transmits more force to the crank
No cause the piston is applying force to the pin/con rod , combustion psi is applied to the pistons surface area (f=pa) which now the piston applies force to the pin/con rod, the more area between the contact of pin and con rod would be your favorite formula p = f / a so the load (force) would be spread across the wider rod eye but the same force will be passed on.
& the engine makes more hp!!!
Torque, guess you don't understand hp either.
Increasing the area of the piston should increase the weight of air drawn into the cyl. If it does that, then the pressure generated from the burn has increased. It is this increase in gas pressure, not the piston area that has created more force.
No cause we've been talking same displacement this whole time just different bore stroke ratios so same volume and..
Again, P = nRT / V, pressure is based on volume of combustion chamber and total volume and of course the amount of fuel and air (nR) and how well it combust (temperature ). Nothing to do with surface area. Read post #129 it's plane as day.
It's amazing you can be this far off and still be so confident :) It's also amazing you just brush aside anything anyone else says ignore any evidence provided and just keep repeating the same baseless analogies.